Code 亦都好簡單, 主要係 define 左每個字母點顯示就已經可以
如果有心機o既, 可以輕易 base on 呢個 code, 焊多幾粒 LED 就可以整中文字型玩
不過俾人催緊我訓, 所以就整住咁多先
int _[] = {0,0,0,0,0, 0,0,0,0,0, 0,0,0,0,0};
int A[] = {0,1,1,1,1, 1,0,1,0,0, 0,1,1,1,1};
int B[] = {1,1,1,1,1, 1,0,1,0,1, 0,1,0,1,0};
int C[] = {0,1,1,1,0, 1,0,0,0,1, 1,0,0,0,1};
int D[] = {1,1,1,1,1, 1,0,0,0,1, 0,1,1,1,0};
int E[] = {1,1,1,1,1, 1,0,1,0,1, 1,0,1,0,1};
int F[] = {1,1,1,1,1, 1,0,1,0,0, 1,0,1,0,0};
int G[] = {0,1,1,1,0, 1,0,1,0,1, 0,0,1,1,0};
int H[] = {1,1,1,1,1, 0,0,1,0,0, 1,1,1,1,1};
int I[] = {0,0,0,0,1, 1,0,1,1,1, 0,0,0,0,1};
int J[] = {1,0,0,0,0, 1,0,0,0,1, 1,1,1,1,1};
int K[] = {1,1,1,1,1, 0,0,1,0,0, 0,1,0,1,1};
int L[] = {1,1,1,1,1, 0,0,0,0,1, 0,0,0,0,1};
int M[] = {1,1,1,1,1, 0,1,1,0,0, 0,1,1,1,1};
int N[] = {1,1,1,1,1, 1,0,0,0,0, 0,1,1,1,1};
int O[] = {0,1,1,1,0, 1,0,0,0,1, 0,1,1,1,0};
int P[] = {1,1,1,1,1, 1,0,1,0,0, 0,1,0,0,0};
int Q[] = {0,1,1,1,1, 1,0,0,1,1, 0,1,1,1,1};
int R[] = {1,1,1,1,1, 1,0,1,0,0, 0,1,0,1,1};
int S[] = {0,1,0,0,1, 1,0,1,0,1, 1,0,0,1,0};
int T[] = {1,0,0,0,0, 1,1,1,1,1, 1,0,0,0,0};
int U[] = {1,1,1,1,1, 0,0,0,0,1, 1,1,1,1,1};
int V[] = {1,1,1,1,0, 0,0,0,0,1, 1,1,1,1,0};
int W[] = {1,1,1,1,0, 0,0,1,1,0, 1,1,1,1,0};
int X[] = {1,1,0,1,1, 0,0,1,0,0, 1,1,0,1,1};
int Y[] = {1,1,0,0,0, 0,0,1,0,0, 1,1,1,1,1};
int Z[] = {1,0,0,1,1, 1,0,1,0,1, 1,1,0,0,1};
int letterSpace;
int dotTime;
void setup()
{
pinMode(2, OUTPUT);
pinMode(3, OUTPUT);
pinMode(4, OUTPUT);
pinMode(5, OUTPUT);
pinMode(6, OUTPUT);
letterSpace = 6;
dotTime = 3;
}
void printLetter(int letter[])
{
int y;
for (y=0; y<5; y++)
{
digitalWrite(y+2, letter[y]);
}
delay(dotTime);
for (y=0; y<5; y++)
{
digitalWrite(y+2, letter[y+5]);
}
delay(dotTime);
for (y=0; y<5; y++)
{
}
delay(dotTime);
for (y=0; y<5; y++)
{
digitalWrite(y+2, 0);
}
delay(letterSpace);
}
void loop()
{
printLetter(H);
printLetter(K);
printLetter(E);
printLetter(P);
printLetter(C);
printLetter(_);
}
[ 本帖最後由 dulllou 於 2009-6-8 01:35 編輯 ] |